1+(1/2)+(1/3)+(1/4)+.............+n

 

1+(1/2)+(1/3)+(1/4)+.............+n

 

//1+(1/2)+(1/3)+(1/4)+.............+n

#include<stdio.h>

int main()

{

    int n,i;

    float sum=0;

    printf("enter number= ");

    scanf("%d",&n);

    for(i=1;i<=n;i++)

         sum=sum+1.0/i;

    {

    printf("\n%.2f\n",sum);

    }

}